14x+49+x^2=0

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Solution for 14x+49+x^2=0 equation: 



14x+49+x^2=0

a = 1; b = 14; c = +49;
Δ = b2-4ac
Δ = 142-4·1·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-14}{2}=-7$

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